Permit: TR-UTL-0825-01444
Permit Details
Status:
Complete
Type:
Right-of-Way (ROW) - Utility
Address:
5555 E 26TH ST
Address NEW:
5555 E 26TH ST
Apply Date:
08/27/2025
Applicant:
Tucson Electric Power
Description:
WO T28314. TEP to remove existing OH conductors to substation and install new OH conductors to new structure in substation.
Permit Reviews
Permit Number - TR-UTL-0825-01444
Permit Status: Complete
Permit Description: WO T28314. TEP to remove existing OH conductors to substation and install new OH conductors to new structure in substation.
| Start Date | Submittal | Complete Date | Status |
|---|---|---|---|
| 08/28/2025 | RIGHT-OF-WAY REVIEW v.1 | 08/28/2025 | APPROVED |
Outstanding Activity Conditions
Permit Number - TR-UTL-0825-01444
Permit Status: Complete
Permit Description: WO T28314. TEP to remove existing OH conductors to substation and install new OH conductors to new structure in substation.
Total Outstanding Activity Conditions - 2
| Date | Name |
|---|---|
| 08/28/2025 | ** PROOF OF NOTIFICATION IS REQUIRED AT THE TIME OF THE PRECONSTRUCTION MEETING. ** PAVEMENT PATCH TYPE SHALL BE IN CONFORMANCE TO THE CURRENT EDITION OF THE CITY OF TUCSON PUBLIC UTILITY ADMINISTRTIVE MANUAL **SIDEWALK CLOSED AHEAD SIGNS SHALL BE PLACED AT THE NEAREST ADA ACCESS RAMPS PER MUTCD CHAPTER 6D. |
| 08/28/2025 | Traffic Control set-up approved between 7AM - 5PM |
Completed Inspections
Permit Status: Complete
Permit Number: TR-UTL-0825-01444
Permit Description: WO T28314. TEP to remove existing OH conductors to substation and install new OH conductors to new structure in substation.
Total Completed Inspections - 4
| Date | Description | Inspector | Results | Comments |
|---|---|---|---|---|
| 12/03/2025 | TRSP - ROW - Barricade - Setup/Routine | Passed | Work is complete | |
| 12/03/2025 | TRSP - ROW - Pre-Activity Field/Pre-Construction Meeting | Passed | Work is complete | |
| 12/03/2025 | TRSP - ROW - Backfill - Placement/Compaction | Passed | Work is complete | |
| 12/03/2025 | TRSP - ROW - Final | Passed | work is complete |